CIE 9701 · A-Level Chemistry

Organic Chemistry
Complete Revision Guide

All reactions, mechanisms, conditions & structural formulas — designed for accessible learning

01

Alkanes

Alkanes are saturated hydrocarbons — they contain only C–C single bonds. General formula: CnH2n+2. They are relatively unreactive due to the strength of C–H and C–C bonds, but they do undergo free radical substitution and combustion.
Oxidation Combustion

Complete Combustion

CH4 + 2O2 CO2 + 2H2O
Condition: Excess O2, high temperature (burning in air)

Incomplete Combustion

CH4 + O2 C + 2H2O   (limited O2 → soot)
Or: 2CH4 + 3O2 2CO + 4H2O
Key fact: CO is a toxic, odourless gas. Complete combustion gives CO₂ + H₂O only.
Substitution Free Radical Halogenation
CH4 + Cl2 CH3Cl + HCl
Condition: UV light (hν), gas phase

⚙ Free Radical Substitution Mechanism

1
Initiation: UV light breaks Cl–Cl homolytically → Cl–Cl → 2Cl• (each Cl gets one electron)
2
Propagation (step 1): Cl• + CH₄ → CH₃• + HCl
3
Propagation (step 2): CH₃• + Cl₂ → CH₃Cl + Cl•
4
Termination: Two radicals combine, e.g. Cl• + Cl• → Cl₂ or CH₃• + Cl• → CH₃Cl
Remember: Curly arrows show electron pair movement. Half-headed arrows (fish-hook) show single electron movement in radical reactions. Multiple substitution can occur giving CH₂Cl₂, CHCl₃, CCl₄.
Thermal Cracking

Thermal Cracking

C10H22 C5H12 + C5H10
Condition: 700–1000°C, high pressure, no catalyst → produces alkenes + alkanes

Catalytic Cracking

Condition: Zeolite catalyst (aluminium silicate), 450°C, lower pressure
Produces branched alkanes + aromatic compounds (petrol)
Why crack? Long-chain alkanes are less useful. Cracking produces shorter, more useful molecules including alkenes (monomers for polymers).
02

Alkenes

Alkenes contain a C=C double bond. General formula: CnH2n. The π bond is electron-rich and makes alkenes electrophilic addition targets. They are much more reactive than alkanes.
Addition Hydrogenation
CH2=CH2 + H2 CH3–CH3
Condition: Ni catalyst, 150°C, high pressure
Industrial use: Hardening vegetable oils to make margarine (converting liquid unsaturated fats to solid saturated fats).
Addition Electrophilic Addition of HBr (+ Markovnikov's Rule)
CH3–CH=CH2 + HBr CH3–CHBr–CH3 (major)
+ CH3–CH2–CH2Br (minor)
Condition: Room temperature, no catalyst needed

⚙ Electrophilic Addition Mechanism

1
Step 1 (slow): The H–Br bond is polarised (Hδ+–Brδ−). The π electrons attack the Hδ+. A C–H bond forms and a carbocation (C+) forms. Br⁻ is released.
2
Step 2 (fast): Br⁻ attacks the carbocation → C–Br bond forms.
3
Markovnikov's Rule: H adds to the carbon with MORE H atoms already. This gives the MORE STABLE (more substituted) carbocation intermediate: secondary > primary.
Addition Bromine Water Test
CH2=CH2 + Br2 CH2Br–CH2Br
Condition: Room temperature, Br₂ in water (orange → colourless)
Test for C=C: Shake with orange bromine water — if it decolorises → alkene is present.

⚙ Mechanism — Electrophilic Addition via Bromonium Ion

1
Br₂ is polarised (Brδ+–Brδ−) near the electron-rich π bond. The π electrons attack Brδ+.
2
A cyclic bromonium ion intermediate forms + Br⁻ leaves.
3
Br⁻ attacks from the back → anti addition product (trans dibromo).
Addition Hydration (making alcohol)
CH2=CH2 + H2O CH3CH2OH
Condition: H₃PO₄ catalyst, 300°C, 60 atm
Industrial route to making ethanol. The steam is passed over the catalyst with ethene.
Oxidation Oxidation with KMnO4
Cold, dilute KMnO₄ (acidified):
CH2=CH2 + [O] + H2O CH2OH–CH2OH (diol)
Purple → colourless: test for C=C

Hot, concentrated KMnO₄:
Breaks the C=C → forms carboxylic acids (from R–CH=) or CO₂+H₂O (from CH₂=)
Polymer Addition Polymerisation
n CH2=CH2 –[CH2–CH2]n (poly(ethene))
Condition: High pressure OR Ziegler–Natta catalyst, moderate temperature
Note: Each monomer must contain a C=C. The double bond opens up to join the chain. Repeat unit shown in square brackets.
03

Benzene & Arenes

Benzene (C6H6) is a planar, cyclic molecule with a delocalised π electron system. All C–C bonds are equivalent (length between single and double). The extra stability of benzene (delocalisation energy ≈ 150 kJ/mol) means it prefers electrophilic substitution (preserving the ring) over addition.
Substitution Nitration
C6H6 + HNO3 C6H5NO2 (nitrobenzene) + H2O
Condition: Conc. H₂SO₄ catalyst, conc. HNO₃, 50°C (below 55°C to avoid dinitration)

⚙ Electrophilic Substitution Mechanism

1
Generate electrophile: H₂SO₄ protonates HNO₃ → NO₂⁺ (nitronium ion) is formed: HNO₃ + H₂SO₄ → NO₂⁺ + HSO₄⁻ + H₂O
2
Attack: π electrons of benzene attack NO₂⁺ → forms a carbocation intermediate (arenium ion). Ring loses aromaticity temporarily.
3
Restoration: H⁺ lost from ring carbon → aromaticity restored. H⁺ + HSO₄⁻ → H₂SO₄ (catalyst regenerated).
Substitution Halogenation (Friedel-Crafts)
C6H6 + Cl2 C6H5Cl (chlorobenzene) + HCl
Condition: AlCl₃ (halogen carrier/Lewis acid catalyst), anhydrous, room temperature

⚙ Mechanism

1
Electrophile generation: AlCl₃ + Cl₂ → Cl⁺ (polarised Cl–Cl via AlCl₃: Cl–Cl→AlCl₃ gives δ+Cl–δ−Cl–AlCl₃)
2
π electrons attack Cl⁺ → arenium ion intermediate.
3
Loss of H⁺ restores ring; H⁺ + AlCl₄⁻ → HCl + AlCl₃ (regenerated).
Substitution Friedel-Crafts Acylation
C6H6 + CH3COCl C6H5COCH3 (phenylethanone / acetophenone) + HCl
Condition: AlCl₃ (anhydrous), room temperature

⚙ Mechanism

1
AlCl₃ activates acyl chloride → generates acylium ion CH₃CO⁺
2
Acylium ion attacks benzene ring (electrophilic substitution as before).
Alkylation uses RCl + AlCl₃ to add an alkyl group. Acylation adds an acyl group (–COR) — preferred as it doesn't give polysubstituted products.
Substitution Sulfonation
C6H6 + H2SO4 C6H5SO3H (benzenesulfonic acid) + H2O
Condition: Fuming H₂SO₄ (oleum), warm (~80°C). Reversible reaction.
Electrophile is SO₃ (from oleum). The reaction is reversible — heating with steam removes SO₃H group.
Reduction Reduction of Nitrobenzene → Aniline
C6H5NO2 + 6[H] C6H5NH2 (aniline / phenylamine) + 2H2O
Condition: Sn metal + conc. HCl, heat (then NaOH to liberate free amine)
Industrial route to dyes & drugs. Sn acts as reducing agent. The product aniline is a primary aromatic amine — key starting material for azo dyes.
04

Alcohols

Alcohols contain the –OH group. They are classified as primary (1°), secondary (2°) or tertiary (3°) based on how many carbon groups are attached to the carbon bearing –OH. This affects their oxidation reactions.
Oxidation Combustion
C2H5OH + 3O2 2CO2 + 3H2O
Condition: Excess O₂, ignition
Oxidation Oxidation with K₂Cr₂O₇
Alcohol TypeProduct (Gentle)Product (Excess)
Primary (1°)
e.g. CH₃CH₂OH
Aldehyde: CH₃CHO
(distil off immediately)
Carboxylic acid: CH₃COOH
(reflux)
Secondary (2°)
e.g. (CH₃)₂CHOH
Ketone: (CH₃)₂C=OKetone only (cannot oxidise further)
Tertiary (3°)
e.g. (CH₃)₃COH
No reaction (no H on C–OH)
Reagent: K₂Cr₂O₇/H₂SO₄ (acidified dichromate)
Colour change: orange → green (Cr²⁷⁺ → Cr³⁺) confirms oxidation
Tollens' reagent (silver mirror test) distinguishes aldehyde from ketone — aldehydes are oxidised further, ketones are NOT.
Elimination Dehydration → Alkene
CH3CH2OH CH2=CH2 + H2O
Condition: Conc. H₂SO₄ or Al₂O₃ (catalyst), 170°C
Note: At 140°C with conc. H₂SO₄, etherification occurs instead: 2CH₃CH₂OH → CH₃CH₂OCH₂CH₃ + H₂O (intermolecular dehydration).
Substitution Making Halogenoalkanes
Using HX:
CH3CH2OH + HBr CH3CH2Br + H2O
Condition: NaBr + conc. H₂SO₄, heat (generates HBr in situ)

Using PCl₅:
C2H5OH + PCl₅ C2H5Cl + POCl₃ + HCl
Condition: Room temperature — also test for –OH group (steamy fumes of HCl)

Using SOCl₂:
C2H5OH + SOCl₂ C2H5Cl + SO₂ + HCl
Condensation Esterification
CH3COOH + C2H5OH CH3COOC2H5 (ethyl ethanoate) + H2O
Condition: Conc. H₂SO₄ catalyst, heat. Equilibrium reaction — remove water to shift right.
Ester functional group: –COO– (ester linkage). The O in –OH of acid bonds with H of alcohol's –OH → H₂O lost. Esters smell fruity.
05

Phenols

Phenol (C6H5OH) has an –OH group directly on a benzene ring. The lone pair on O delocalises into the ring, activating it (especially at ortho/para positions) and making O–H more acidic than in alcohols (but still a weak acid, pKa ≈ 10).
Acid-Base Phenol as an Acid
C6H5OH + NaOH C6H5O⁻Na⁺ (sodium phenoxide) + H2O
Condition: Room temperature, aqueous NaOH
C6H5OH + Na2CO3 NO REACTION
Phenol is a WEAKER acid than carbonic acid (H₂CO₃) — cannot displace CO₂
Distinguish from carboxylic acid: Carboxylic acids react with Na₂CO₃ to give CO₂ bubbles; phenol does NOT.
Condensation Ester Formation with Phenol
C6H5OH + CH3COCl C6H5OOCCH3 (phenyl ethanoate) + HCl
Condition: Room temperature, no catalyst needed (acyl chloride is reactive enough)
Why use acyl chloride, not carboxylic acid? Phenol is a weaker nucleophile than alcohol; acid catalyst + heating not enough. Acyl chlorides react at room temperature.
Substitution Bromination of Phenol
C6H5OH + 3Br2(aq) 2,4,6-tribromophenol + 3HBr
Condition: Room temperature, bromine WATER (no catalyst needed — ring is activated)
Bromine water decolorises immediately + white precipitate forms
Compare with benzene: Benzene needs a Lewis acid catalyst (AlBr₃) to react with Br₂. Phenol is so reactive it reacts with Br₂ in water directly — and gives trisubstituted product.
Test Phenol + FeCl₃
C6H5OH + FeCl3(aq) Purple/violet complex
Condition: Add a few drops of FeCl₃ solution to phenol
Diagnostic test: Purple/violet colour with neutral FeCl₃ confirms phenolic –OH group is present.
06

Halogenoalkanes

Halogenoalkanes (haloalkanes) contain a C–X bond (X = F, Cl, Br, I). The C–X bond is polar (Cδ+–Xδ−) making carbon electrophilic and susceptible to nucleophilic substitution and elimination.
Substitution SN1 vs SN2 Mechanism
FeatureSN1SN2
Steps2 (stepwise)1 (concerted)
IntermediateCarbocationNone
Favoured byTertiary halidesPrimary halides
Rate depends on[RX] only[RX] and [Nu⁻]
StereochemistryRacemisationInversion (Walden)

⚙ SN2 Mechanism (e.g. CH₃Br + OH⁻)

1
OH⁻ attacks from the back (180°) of C–Br bond. C–Br starts to break simultaneously.
2
Transition state: HO···C···Br (pentavalent)
3
Br⁻ leaves → C–OH forms. Configuration inverted (umbrella effect).

⚙ SN1 Mechanism (e.g. (CH₃)₃CBr + H₂O)

1
Step 1 (slow, RDS): C–Br ionises → stable 3° carbocation + Br⁻
2
Step 2 (fast): Nucleophile (H₂O, OH⁻) attacks carbocation from either face → racemisation
Substitution Nucleophilic Substitution Reactions
NucleophileReagent & ConditionsProduct
OH⁻ (hydrolysis)NaOH(aq), warmAlcohol (–OH)
CN⁻KCN in ethanol, warmNitrile (–CN) — chain extended by 1C
NH₃Excess conc. NH₃, heat in sealed tubePrimary amine (–NH₂)
RNH₂ (amine)Excess RNH₂, heatSecondary amine
I⁻ (Finkelstein)NaI in acetoneIodoalkane
Hydrolysis example:
CH3CH2Br + NaOH(aq) CH3CH2OH + NaBr
Condition: aqueous NaOH, warm
Elimination E2 Elimination → Alkene
CH3CH2Br + NaOH CH2=CH2 + NaBr + H2O
Condition: NaOH in ethanol (not water), heat
SN2 vs E2: Aqueous NaOH → substitution (alcohol). Ethanolic NaOH + heat → elimination (alkene). Tertiary halides favour elimination more than primary.

⚙ E2 Mechanism

1
OH⁻ acts as BASE, abstracting H from β-carbon (the carbon next to C–Br).
2
As H–C bond breaks, C=C π bond forms simultaneously and Br⁻ leaves. All in one concerted step.
Reactivity C–X Bond Strength & Reactivity
Reactivity order: C–I > C–Br > C–Cl > C–F
Bond enthalpy (kJ/mol): C–F(484) > C–Cl(338) > C–Br(276) > C–I(238)
Weaker bond = easier to break = faster reaction
Test for halogenoalkanes: Add AgNO₃ in ethanol after hydrolyis. AgCl = white ppt, AgBr = cream ppt, AgI = yellow ppt. Solubility in NH₃ confirms: AgCl dissolves in dilute NH₃; AgBr in conc. NH₃; AgI insoluble.
07

Carbonyl Compounds: Aldehydes & Ketones

Both contain the C=O (carbonyl) group. Aldehydes have –CHO at the end of a chain; ketones have C=O within the chain. The C=O is polar (Cδ+) → susceptible to nucleophilic addition.
Reduction Reduction with NaBH₄ / LiAlH₄
Aldehyde → Primary alcohol:
CH3CHO + 2[H] CH3CH2OH

Ketone → Secondary alcohol:
CH3COCH3 + 2[H] CH3CH(OH)CH3
Reagent: NaBH₄ in water/ethanol (mild) OR LiAlH₄ in dry ether (powerful)

⚙ Nucleophilic Addition Mechanism

1
H⁻ (hydride ion from NaBH₄) attacks the electrophilic Cδ+ of C=O.
2
C=O π bond breaks → alkoxide ion (C–O⁻) forms.
3
Protonation (H₂O or H⁺) → alcohol.
Addition Addition of HCN (Cyanohydrin)
CH3CHO + HCN CH3CH(OH)CN (2-hydroxypropanenitrile)
Condition: KCN/HCN, dilute acid, room temperature. NaCN + H₂SO₄ generates HCN safely.

⚙ Mechanism

1
CN⁻ (nucleophile) attacks Cδ+ of C=O → C–CN bond forms, C–O⁻ created.
2
Protonation of O⁻ by H⁺ (from HCN dissociation) → –OH group.
Importance: Extends carbon chain by 1C. The –CN can be hydrolysed to –COOH (carboxylic acid) — useful in synthesis. Creates a chiral centre → racemic mixture forms.
Condensation 2,4-DNPH Test (Brady's Reagent)
R–C=O + H2N–NHRC6H3(NO2)2 Orange/yellow precipitate + H2O
Condition: 2,4-dinitrophenylhydrazine solution, add to carbonyl compound
Test result: Orange/yellow precipitate = carbonyl group present. Recrystallise the ppt and measure melting point to identify which specific aldehyde or ketone.
Test Distinguishing Aldehyde from Ketone
TestReagentAldehydeKetone
Tollens'AgNO₃ + NH₃ (silver mirror reagent)Silver mirror on tube wallNo reaction
Fehling'sBlue Cu²⁺ solution, warmBrick-red ppt (Cu₂O)No reaction
K₂Cr₂O₇Acidified dichromateOrange → greenNo colour change
Tollens: RCHO + 2[Ag(NH₃)₂]⁺ + 2OH⁻ RCOO⁻ + 2Ag↓ + 4NH₃ + H₂O
Key: Aldehydes can be oxidised (they have H on C=O); ketones cannot (no H on C=O carbon).
Test Triiodomethane (Iodoform) Reaction
CH3COR + 3I2 + 3NaOH CHI3 (yellow ppt) + RCOONa + 3NaI + 3H₂O
Condition: I₂ + NaOH (warm)
Positive test: Yellow precipitate of CHI₃ (triiodomethane) with antiseptic smell. Tests for CH₃CO– (methyl ketones like propanone) AND CH₃CH(OH)– (ethanol and secondary alcohols with CH₃– next to C–OH).
08

Carboxylic Acids & Derivatives

Carboxylic acids contain –COOH. They are weak acids. Derivatives include: acyl chlorides (–COCl), acid anhydrides (–CO–O–CO–), esters (–COO–), and amides (–CONH₂). Reactivity order: acyl chloride > anhydride > ester > amide.
Acid Reactions of Carboxylic Acids
With bases (Na, NaOH, Na₂CO₃):
CH3COOH + NaOH → CH3COONa + H₂O
2CH3COOH + Na2CO32CH3COONa + CO₂↑ + H₂O

With alcohols (esterification):
CH3COOH + CH3OH CH3COOCH3 + H₂O
Condition: Conc. H₂SO₄ catalyst, heat
Reduction Reduction of Carboxylic Acids
CH3COOH + 4[H] CH3CH2OH + H2O
Condition: LiAlH₄ in dry ether (NaBH₄ is NOT strong enough for carboxylic acids)
Substitution Reactions of Acyl Chlorides (–COCl)
NucleophileReactionProductConditions
H₂OHydrolysisCarboxylic acid + HClCold water, vigorous
ROH (alcohol)EsterificationEster + HClRoom temperature
NH₃Amide formationAmide + NH₄ClRoom temperature, excess NH₃
RNH₂ (amine)N-substituted amideRCONHR + HClRoom temperature
ArOH (phenol)EsterificationPhenyl ester + HClRoom temperature
CH3COCl + CH3OH CH3COOCH3 + HCl (steamy fumes)

⚙ Nucleophilic Acyl Substitution Mechanism

1
Nucleophile (e.g. –OH of alcohol) attacks electrophilic C of C=O in acyl chloride → tetrahedral intermediate.
2
Cl⁻ leaves as the C=O reforms → ester product + HCl.
Substitution Reactions of Acid Anhydrides
With water:
(CH3CO)2O + H2O → 2CH3COOH

With alcohol:
(CH3CO)2O + C2H5OH → CH3COOC2H5 + CH3COOH

With ammonia:
(CH3CO)2O + 2NH3CH3CONH2 + CH3COONH₄
Safer than acyl chloride (no HCl fumes); used in aspirin synthesis
Hydrolysis Ester Hydrolysis
Acid hydrolysis (reversible):
CH3COOC2H5 + H2O CH3COOH + C2H5OH
Condition: Dilute H₂SO₄, heat under reflux

Base (saponification) — irreversible:
CH3COOC2H5 + NaOH CH3COO⁻Na⁺ + C2H5OH
Condition: NaOH(aq), heat under reflux
Saponification (base hydrolysis) is irreversible because the carboxylate ion (RCOO⁻) is a poor electrophile — the alcohol cannot re-attack it to reform ester.
Hydrolysis Amide Reactions
Acid hydrolysis:
CH3CONH2 + H2O + HCl CH3COOH + NH₄Cl

Base hydrolysis:
CH3CONH2 + NaOH CH3COO⁻Na⁺ + NH₃↑
Condition: Dilute acid or base, heat under reflux

Reduction of amide → amine:
CH3CONH2 + 4[H] CH3CH2NH2 + H2O
Condition: LiAlH₄, dry ether
09

Nitrogen Compounds

Includes amines (–NH₂, –NHR, –NR₂), amides (–CONH₂), nitriles (–C≡N), and amino acids. Amines are bases due to the lone pair on N. Primary amines can act as nucleophiles.
Base Amines as Bases & Nucleophiles
As base:
CH3NH2 + HCl CH3NH3⁺Cl⁻ (methylammonium chloride)

Basicity order:
Aliphatic: 2° > 1° > NH₃ > 3° (in water — due to solvation)
Aromatic amines (e.g. aniline C₆H₅NH₂) are MUCH weaker bases than aliphatic amines
(lone pair delocalised into benzene ring → less available for protonation)
Synthesis Making Amines
MethodStarting MaterialReagent & ConditionsProduct
From halogenoalkaneRXExcess NH₃, heat in sealed tubeRNH₂ (primary amine) — mixture of 1°/2°/3°/salt
Reduction of nitrileR–CNLiAlH₄ / dry ether OR H₂/NiR–CH₂NH₂ (1° amine, chain +1C)
Reduction of amideRCONH₂LiAlH₄ / dry etherRCH₂NH₂
Reduction of nitrobenzeneC₆H₅NO₂Sn + conc. HCl, then NaOHC₆H₅NH₂ (aniline)
Condensation Amines + Acyl Chlorides → Amides
CH3NH2 + CH3COCl CH3CONHCH3 (N-methylethanamide) + HCl
Condition: Room temperature — very rapid reaction
Condensation Diazonium Salts & Azo Dyes
Step 1 — Diazotisation:
C6H5NH2 + HCl + NaNO2 [C6H5N≡N]⁺Cl⁻ (benzene diazonium chloride)
Condition: Below 5°C, HCl + NaNO₂ (NaNO₂ + HCl generates HNO₂ in situ)

Step 2 — Coupling reaction (azo dye):
[C6H5N≡N]⁺ + C6H5OH (phenol, alkaline) C6H5–N=N–C6H4OH (orange/yellow azo dye)
Condition: Alkaline solution (NaOH), 0–5°C
Why keep below 5°C? Diazonium salts decompose above 10°C → phenol + N₂. Cold temperature stabilises them for coupling reactions.
Condensation Amino Acids & Peptide Bond
Structure of amino acid (zwitterion at neutral pH):
⁺H₃N–CH(R)–COO⁻

Peptide bond formation (condensation):
H₂N–CHR–COOH + H₂N–CHR'–COOH H₂N–CHR–CO–NH–CHR'–COOH + H₂O
Condition: Heat (in biology: enzyme-catalysed ribosome reaction)
Peptide bond: –CO–NH– linkage. Hydrolysis (acid/base + heat) breaks it back to amino acids. This is how proteins are broken down in digestion.
10

Polymer Chemistry

Polymers are long-chain molecules made from many repeating monomer units. Two main types: Addition polymers (from alkenes, no by-product) and Condensation polymers (from bifunctional monomers, with small by-product like H₂O or HCl).
Addition Addition Polymerisation
MonomerPolymerUses
CH₂=CH₂ (ethene)poly(ethene) –[CH₂–CH₂]nPlastic bags, bottles
CH₂=CHCl (chloroethene)PVC –[CH₂–CHCl]nPipes, flooring
CH₂=CHCN (propenenitrile)PAN –[CH₂–CHCN]nAcrylic fibres
CF₂=CF₂ (tetrafluoroethene)PTFE –[CF₂–CF₂]nNon-stick, wire insulation
CH₂=C(CH₃)COOCH₃Perspex (PMMA)Transparent plastic
n CH₂=CHX –[CH₂–CHX]n
No by-product formed. Double bond opens up.
Condensation Polyesters
PET (Terylene/Dacron):
n HO–(CH₂)₂–OH (ethane-1,2-diol) + n HOOC–C₆H₄–COOH (benzene-1,4-dicarboxylic acid) –[O–(CH₂)₂–O–CO–C₆H₄–CO]n + n H₂O
Condition: High temperature, catalyst. Repeat unit has ester linkage –COO–
Monomers needed: A diol (2 × –OH) + a dicarboxylic acid (2 × –COOH). OR a hydroxy acid (–OH and –COOH in same molecule, e.g. lactic acid → poly(lactic acid)).
Condensation Polyamides (Nylon)
Nylon-6,6:
n H₂N–(CH₂)₆–NH₂ (1,6-diaminohexane) + n ClOC–(CH₂)₄–COCl (hexanedioyl dichloride) –[NH–(CH₂)₆–NH–CO–(CH₂)₄–CO]n + n HCl
Condition: Room temperature (interfacial polymerisation) OR heat with diacid

Nylon-6 (from caprolactam — ring-opening):
n [–NH–(CH₂)₅–CO–] –[NH–(CH₂)₅–CO]n
Amide bond: –CO–NH–. Hydrogen bonding between chains makes nylon strong. Found in ropes, clothing, toothbrush bristles.
Natural Proteins & DNA as Natural Polymers
Proteins: condensation polymer of amino acids → peptide bonds (–CONH–)
Starch/cellulose: condensation polymer of glucose → glycosidic bonds
DNA: condensation polymer of nucleotides → phosphodiester bonds
Hydrolysis of proteins: Acid (HCl) or base (NaOH) + heat breaks peptide bonds → mixture of amino acids. Enzymes do this in digestion at body temperature.
Properties Biodegradability of Polymers
Polymer typeBiodegradable?Reason
Addition (e.g. polyethene)NOOnly C–C and C–H bonds — very strong; microbes cannot break them
Condensation (polyesters, polyamides)YES (slowly)Ester/amide links can be hydrolysed by water, acid, base or enzymes
Proteins, starchYESEnzyme-catalysed hydrolysis by microorganisms
Green chemistry: Poly(lactic acid) PLA — made from fermented starch — is a biodegradable polyester. Used in packaging and medical implants.

Self Assessment

📝 20-Question Quiz

Test your understanding of all 10 topics. Select an answer to reveal instant feedback.

Question 01 · Alkanes
What are the THREE stages of the free radical substitution of methane with chlorine?
Question 02 · Alkanes
UV light is used in the free radical halogenation of methane. What does UV light do?
Question 03 · Alkenes
Propene (CH₃CH=CH₂) reacts with HBr. Which product is the MAJOR product according to Markovnikov's Rule?
Question 04 · Alkenes
Bromine water (orange) is added to an unknown compound and it decolourises. What does this indicate?
Question 05 · Benzene
What electrophile is generated when benzene is nitrated using HNO₃/H₂SO₄?
Question 06 · Benzene
Why does benzene prefer electrophilic SUBSTITUTION rather than electrophilic ADDITION?
Question 07 · Alcohols
A secondary alcohol is heated with acidified K₂Cr₂O₇. What is the product?
Question 08 · Alcohols
Ethanol is heated with conc. H₂SO₄ at 170°C. What is the main product?
Question 09 · Phenols
Phenol is added to bromine water (no catalyst). What is observed and what is the product?
Question 10 · Halogenoalkanes
Which reagent and conditions would convert bromoethane to ethylamine (CH₃CH₂NH₂)?
Question 11 · Halogenoalkanes
Why is C–I bond more reactive than C–F bond in nucleophilic substitution?
Question 12 · Carbonyl Compounds
Tollens' reagent (ammoniacal AgNO₃) produces a silver mirror with compound X but NOT with compound Y. Both X and Y give an orange precipitate with 2,4-DNPH. What are X and Y?
Question 13 · Carbonyl Compounds
What is the product when HCN is added to ethanal (CH₃CHO)?
Question 14 · Carboxylic Acids
Why is base (saponification) hydrolysis of an ester irreversible, but acid hydrolysis is reversible?
Question 15 · Carboxylic Acids
An acyl chloride reacts with ammonia. What are the products?
Question 16 · Nitrogen Compounds
Why is aniline (C₆H₅NH₂) a much weaker base than methylamine (CH₃NH₂)?
Question 17 · Nitrogen Compounds
In diazotisation of aniline, why must the temperature be kept BELOW 5°C?
Question 18 · Polymers
What type of polymerisation makes PET (polyester) and what is the by-product?
Question 19 · Polymers
Why are addition polymers (like poly(ethene)) NOT biodegradable?
Question 20 · Mixed Topics
A compound gives a yellow precipitate with I₂/NaOH (iodoform test) AND decolourises acidified K₂Cr₂O₇. Which of the following could it be?